Calculating Acceleration of a Sphere Thrown Upward

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Homework Help Overview

The discussion revolves around calculating the acceleration of a sphere thrown upward, specifically after 1.5 seconds, with initial conditions including a height of 13 meters and an initial velocity of 20 m/s. The problem is situated within the context of kinematics and gravitational acceleration.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to find acceleration, questioning the role of initial height and the meaning of acceleration in this context. There is confusion regarding the distinction between acceleration and velocity, as well as the implications of the given answer choices.

Discussion Status

Some participants have suggested using specific kinematic equations, while others express uncertainty about the number of unknowns in the equations. There is a recognition of the gravitational acceleration as a key factor, with some participants reconsidering their initial assumptions about the problem.

Contextual Notes

Participants note the potential confusion between acceleration and velocity, as well as the significance of the height of 13 meters in relation to the problem. The discussion reflects a mix of interpretations regarding the nature of the question and the expected answer.

ch3570r
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I know I already have a topic for a previous question, but here's another simple one, but I think I am just missing some simple equations.

"What is the magnitude of acceleration after 1.5 seconds of a sphere thrown upward from a height of 13 meters at 20 m/s^2?"

Choices
a) 5.3 m/s^2
b) 9.8 m/s^2
c) 15 m/s^2
d) 32 m/s^2
e) 390 m/s^2

I realize these are quite obvious answer choices, and the answer is most likely D, but I don't know how to get it. I only have the "four kinematics" equations to work with, but I think there are other equations I can use for this. How does the height of 13m effect my answer, if it indeed does.
 
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Use the equation [tex]y = y_{0} + v_{y0}t + \frac{1}{2}a_{y}t^{2}[/tex]
 
courtrigrad said:
Use the equation [tex]y = y_{0} + v_{y0}t + \frac{1}{2}a_{y}t^{2}[/tex]

ok, using that equation, doesn't it leave me with two unknowns? I have time, initial distance in y, and initial velocity in y. I don't have the total distance in y, or the acceleration, which I am trying to find. Is that right, or am I mistaken...I might need to find total distance first, and then the acceleration.
 
ch3570r said:
I know I already have a topic for a previous question, but here's another simple one, but I think I am just missing some simple equations.

"What is the magnitude of acceleration after 1.5 seconds of a sphere thrown upward from a height of 13 meters at 20 m/s^2?"

Choices
a) 5.3 m/s^2
b) 9.8 m/s^2
c) 15 m/s^2
d) 32 m/s^2
e) 390 m/s^2

I realize these are quite obvious answer choices, and the answer is most likely D, but I don't know how to get it. I only have the "four kinematics" equations to work with, but I think there are other equations I can use for this. How does the height of 13m effect my answer, if it indeed does.
What causes the object to accelerate? What is the magnitude of this acceleration? This is more of a "did you memorize this constant?" kind of question than a problem about applying kinematics equations. Lastly why do you think it's D?
 
well, the acceleration down would be gravity (9.8 m/s^2)...wait, so the answer is B!? I was thinking that because the object is traveling at 20m/s^2, after 1.5 seconds, it would be slighty over 20m, and the closest answer is D. But I guess if its asking for the "magnitude" of the acceleration, it would be gravity.
 
ch3570r said:
well, the acceleration down would be gravity (9.8 m/s^2)...wait, so the answer is B!? I was thinking that because the object is traveling at 20m/s^2, after 1.5 seconds, it would be slighty over 20m, and the closest answer is D. But I guess if its asking for the "magnitude" of the acceleration, it would be gravity.

Yes the answer is B. And no after 1.5 seconds the object is not traveling at 20m/s^2 that is an acceleration not a velocity! Acceleration is measure in units of meteres per second squared and near the surface of the Earth the value of acceleration due to gravity is nearly constant at 9.8m/s^2.
 

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