Calculating Acceleration of a Sphere Thrown Upward

  • Thread starter Thread starter ch3570r
  • Start date Start date
  • Tags Tags
    Acceleration
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
5 replies · 10K views
ch3570r
Messages
38
Reaction score
0
I know I already have a topic for a previous question, but here's another simple one, but I think I am just missing some simple equations.

"What is the magnitude of acceleration after 1.5 seconds of a sphere thrown upward from a height of 13 meters at 20 m/s^2?"

Choices
a) 5.3 m/s^2
b) 9.8 m/s^2
c) 15 m/s^2
d) 32 m/s^2
e) 390 m/s^2

I realize these are quite obvious answer choices, and the answer is most likely D, but I don't know how to get it. I only have the "four kinematics" equations to work with, but I think there are other equations I can use for this. How does the height of 13m effect my answer, if it indeed does.
 
Physics news on Phys.org
Use the equation [tex]y = y_{0} + v_{y0}t + \frac{1}{2}a_{y}t^{2}[/tex]
 
courtrigrad said:
Use the equation [tex]y = y_{0} + v_{y0}t + \frac{1}{2}a_{y}t^{2}[/tex]

ok, using that equation, doesn't it leave me with two unknowns? I have time, initial distance in y, and initial velocity in y. I don't have the total distance in y, or the acceleration, which I am trying to find. Is that right, or am I mistaken...I might need to find total distance first, and then the acceleration.
 
ch3570r said:
I know I already have a topic for a previous question, but here's another simple one, but I think I am just missing some simple equations.

"What is the magnitude of acceleration after 1.5 seconds of a sphere thrown upward from a height of 13 meters at 20 m/s^2?"

Choices
a) 5.3 m/s^2
b) 9.8 m/s^2
c) 15 m/s^2
d) 32 m/s^2
e) 390 m/s^2

I realize these are quite obvious answer choices, and the answer is most likely D, but I don't know how to get it. I only have the "four kinematics" equations to work with, but I think there are other equations I can use for this. How does the height of 13m effect my answer, if it indeed does.
What causes the object to accelerate? What is the magnitude of this acceleration? This is more of a "did you memorize this constant?" kind of question than a problem about applying kinematics equations. Lastly why do you think it's D?
 
well, the acceleration down would be gravity (9.8 m/s^2)...wait, so the answer is B!? I was thinking that because the object is traveling at 20m/s^2, after 1.5 seconds, it would be slighty over 20m, and the closest answer is D. But I guess if its asking for the "magnitude" of the acceleration, it would be gravity.
 
ch3570r said:
well, the acceleration down would be gravity (9.8 m/s^2)...wait, so the answer is B!? I was thinking that because the object is traveling at 20m/s^2, after 1.5 seconds, it would be slighty over 20m, and the closest answer is D. But I guess if its asking for the "magnitude" of the acceleration, it would be gravity.

Yes the answer is B. And no after 1.5 seconds the object is not traveling at 20m/s^2 that is an acceleration not a velocity! Acceleration is measure in units of meteres per second squared and near the surface of the Earth the value of acceleration due to gravity is nearly constant at 9.8m/s^2.