Calculating Adiabatic Cooling at 1000 Meters Using Atmospheric Law

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SUMMARY

The discussion focuses on calculating adiabatic cooling for a pocket of air rising 1000 meters using the atmospheric law. The pressure at this altitude is determined to be 90202 Pa, or approximately 0.89 atm. The user initially misapplied the adiabatic equations, assuming the specific heat ratio γ as 5/7 instead of the correct value of 7/5, which led to incorrect calculations indicating heating instead of cooling. Once the correct value of γ was used, the calculations aligned with the expected cooling behavior.

PREREQUISITES
  • Understanding of the atmospheric law, specifically the equation P = P0 * e-Mgz/RT.
  • Familiarity with adiabatic processes and the equations PVγ = constant and TVγ-1 = constant.
  • Knowledge of specific heat capacities, particularly the ratio γ = Cp/Cv.
  • Basic principles of thermodynamics related to gas behavior under pressure and volume changes.
NEXT STEPS
  • Study the derivation and application of the atmospheric law in different altitudes.
  • Learn about the implications of the specific heat ratio γ in various gases and its effect on thermodynamic processes.
  • Explore detailed examples of adiabatic cooling calculations in meteorology and environmental science.
  • Investigate the relationship between pressure, volume, and temperature in real gas behavior versus ideal gas assumptions.
USEFUL FOR

Students in physics or engineering, meteorologists, and anyone interested in understanding thermodynamic processes related to atmospheric phenomena.

EzequielSeattle
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Homework Statement


A pocket of air rises 1000 meters. Estimate how much it cools. Use the atmospheric law to determine pressure at 1000 meters.

Homework Equations


P = P0 * e-Mgz/RT
PVγ = constant
TVγ-1 = constant

The Attempt at a Solution


Using the atmospheric law, I found the pressure at 1000 meters to be 90202 Pa, or about 0.89 atm. I'm not sure how to use the adiabatic equations. I just assumed V1 was 1 m3, and also assumed that γ=(5/7), as the atmosphere is mainly diatomic. Plugging these in, I got that the gas expands to about 1.09 m3, but when I tried to plug that into my last equation, I got that the gas actually HEATS up, which I know is wrong. What did I do wrong? Please help!
 
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EzequielSeattle said:

Homework Statement


A pocket of air rises 1000 meters. Estimate how much it cools. Use the atmospheric law to determine pressure at 1000 meters.

Homework Equations


P = P0 * e-Mgz/RT
PVγ = constant
TVγ-1 = constant

The Attempt at a Solution


Using the atmospheric law, I found the pressure at 1000 meters to be 90202 Pa, or about 0.89 atm. I'm not sure how to use the adiabatic equations. I just assumed V1 was 1 m3, and also assumed that γ=(5/7), as the atmosphere is mainly diatomic. Plugging these in, I got that the gas expands to about 1.09 m3, but when I tried to plug that into my last equation, I got that the gas actually HEATS up, which I know is wrong. What did I do wrong? Please help!

What is gamma? it should be the ratio of Cp/Cv, correct? Which is larger, Cp or Cv ? Should gamma be greater or less than one?
 
Thank you! I was accidentally using γ=5/7 instead of 7/5. It works now.
 

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