Calculating angle between two complex numbers

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To show that the angles of z1 and z3 differ by an integer multiple of pi/2, one can analyze the vectors represented by the complex numbers in the complex plane. The discussion highlights that z1 = 3 + j and z2 = -5 + 5j combine to form z3 = -2 + 6j. The suggestion to use the dot product indicates that if the vectors are perpendicular, their angle difference will indeed be pi/2. MATLAB calculations confirm that the angle between these vectors aligns with this relationship. Thus, the angles of z1 and z3 differ by an integer multiple of pi/2, confirming their perpendicularity.
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so I have z1 = 3 + j, z2 = -5 + 5j, z3 = z1+z2 = -2 + 6j

the question is, show that angle(z1) and angle(z1 + z2) differ by an integer multiple of pi/2.

I tried doing it this way
arctan(z1/z3), but then I always end up with a number that doesn't work. I know that arctan(x) cannot equal pi/2. Is there another way t rewrite it? I computed it using MATLAB and it gave me pi/2.
 
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Just draw the corresponding vectors ##\langle 3,1\rangle## and ##\langle -1,3\rangle## and look at their dot product.
 
Perhaps you can utilize that pi/2 means the two complex numbers, when viewed as vectors in the complex plane, must be perpendicular to each other.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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