Calculating angle between two vectors

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To calculate the angle between the vectors a = 1.0 ihat + 5.0 jhat + 1.0 khat and b = 6.0 ihat + 3.0 jhat + 4.0 khat, use the scalar product formula a·b = ab cos θ. First, compute the dot product a·b by summing the products of their corresponding components: a·b = axbx + ayby + azbz. Then, find the magnitudes of both vectors using the Pythagorean theorem. Finally, rearrange the scalar product equation to solve for θ using the arccos function. This approach will yield the angle between the two vectors.
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Homework Statement



Use the definition of scalar product, a·b = ab cos θ, and the fact that a·b = axbx + ayby + azbz to calculate the angle between the two vectors given by a = 1.0 ihat + 5.0 jhat + 1.0 khat and b = 6.0 ihat + 3.0 jhat + 4.0 khat.


Homework Equations



a·b = ab cos θ

The Attempt at a Solution



i really don't have any clue were to start
 
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jpd5184 said:

Homework Statement



Use the definition of scalar product, a·b = ab cos θ, and the fact that a·b = axbx + ayby + azbz to calculate the angle between the two vectors given by a = 1.0 ihat + 5.0 jhat + 1.0 khat and b = 6.0 ihat + 3.0 jhat + 4.0 khat.


Homework Equations



a·b = ab cos θ

The Attempt at a Solution



i really don't have any clue were to start
Write out the expression for \theta in terms of the length of a x length of b and a_xb_x + a_yb_y + a_zb_z (hint: you need the arccos function and pythagoras' theorem).

AM
 

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