Calculating total Coulomb force vector ?

Click For Summary
SUMMARY

The discussion focuses on calculating the total Coulomb force vector acting on a positive charge (+q) in a configuration with three negative charges (−q) arranged in a square. The participants utilize the vector form of Coulomb's force, represented as F = (kq1q2/r^2) rhat, and break down the forces into three components: F1 (horizontal), F2 (diagonal), and F3 (vertical). The correct approach involves maintaining a consistent Cartesian coordinate system and summing the x and y components of the forces to determine the net force vector.

PREREQUISITES
  • Understanding of Coulomb's Law and its vector form
  • Familiarity with vector components in Cartesian coordinates
  • Basic knowledge of trigonometry for calculating diagonal distances
  • Ability to perform vector addition
NEXT STEPS
  • Study the application of Coulomb's Law in different charge configurations
  • Learn about vector addition techniques in physics
  • Explore the implications of coordinate system transformations in physics problems
  • Practice problems involving multiple charges and net force calculations
USEFUL FOR

Students studying electrostatics, physics enthusiasts, and anyone looking to deepen their understanding of vector forces in charge interactions.

starstruck_
Messages
185
Reaction score
8

Homework Statement


Consider a configuration consisting one +q charge ( upper right) and three −q charges, arranged in a square.

Side lengths = d.

Calculate the total F force vector acting on charge +q.

Homework Equations


Vector form of culomb’s force
F=( kq1q2/r^2) rhat

(rhat for unit vector - I’m on my phone so I can’t really tyupe it out properly, sorry)

The Attempt at a Solution


Split into 3 Force vector (between +q and each charge ). F1 is horizontal, F2 is the diagonal force vector, F3 is the vertical force vector.

F1 = (-ke^2/r^2)rhat

r= d
rhat= (ihat)
Or is it rhat= d( ihat )?

Anyways,
F1= ((-ke^2)/d^2))(ihat)

F2 = (-ke^2/r^2)(rhat)
r = sqrt(d^2+d^2)
r= sqrt(2)d
rhat = r vector/|r vector|
Assuming tail at origin
r vector = <d,d>
rhat= d(ihat)+d(jhat)/(sqrt(2)d)

F2= (-ke^2/(2d^2))(d(ihat)/sqrt(2)d)+ (-ke^2/(2d^2))(d(jhat)/sqrt(2)d)

F2 =(-ke^2/(2sqrt(2)d^3))(d(ihat))+(-ke^2/(2sqrt(2)d^3))(d(jhat))

F3 = (-ke^2/r^2)(rhat)

r= d
rhat= jhat or is it rhat = d(jhat)?

F3= (-ke^2/d^2)(jhat)

And then I would just add all of the components together.

I’m just wondering if I did this rhat business correctly ?

It said to use the vector form of the Coulomb force, so I tried- I’m not used to working with forces in this manner.

((Also sorry if it’s really hard to understand what I did, I can try to write it down and post a picture of my work if possible)).
 
Physics news on Phys.org
Your basic approach is OK.

It's convenient in this forum to use bold letters to convey vectors.
So r_hat = r, i_hat = i, j_hat = j, r =r cosθ i + r sinθ j and F = Fx i + Fy j.

When you introduce r you are doing coordinate system switching between cartesian (x,y) and polar (r,θ) coordinates. But this is not necessary. You can just stick with cartesian. So for example F2 = kq/d2 i + kq/d2 j and so on for F1 and F3. Then just add all the x and y components separately to get the net force in the i and j directions. Note that you don't calculate r2 =2d2separately. At the end you can still compute r (and θ) if you want.
 
  • Like
Likes   Reactions: starstruck_

Similar threads

  • · Replies 6 ·
Replies
6
Views
1K
Replies
17
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
Replies
3
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K