Calculating Arc-Length Function for Smooth Curve g

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Discussion Overview

The discussion revolves around the arc-length function for a smooth curve g: [a,b] -> R^n, specifically addressing the differentiability of the arc-length function and the continuity of the norm of the derivative. Participants explore the implications of smoothness and regularity on the continuity of the norm function.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant presents the arc-length function s(t) and questions the differentiability, specifically the continuity of ||dg/du|| when g is merely smooth.
  • Another participant asserts that the norm function is continuous, suggesting that this confirms the continuity of ||dg/du||.
  • A third participant clarifies that the continuity of ||dg/du|| follows from the combination of the continuity of the norm function and the continuity of the derivative of a smooth function.
  • A later reply acknowledges the concern about the continuity of the norm after applying it to dg/du but concludes that the continuity holds due to the composition of continuous functions.

Areas of Agreement / Disagreement

Participants express differing views on the implications of smoothness for the continuity of the norm of the derivative. While some assert that continuity follows from the properties of smooth functions, others raise concerns about the application of the norm affecting continuity.

Contextual Notes

The discussion highlights the dependence on definitions of smoothness and regularity, as well as the assumptions regarding the continuity of functions involved. There is no resolution on whether the continuity of ||dg/du|| can be universally applied without additional conditions.

Buri
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I have the arc-length function defined for a smooth curve g: [a,b] -> R^n as starting at g(t_0) as:

s(t) = integral [t_0, t] ||dg/du|| du.

The text says this is differentiable, so ds/dt = ||dg/du||. But I don't see why. I know that g is smooth, but the norm causes problems and so to apply the fundamental theorem of calculus I would have to know that ||dg/du|| is continuous. If g is also regular then ||dg/du|| is smooth, so it would follow, but I don't see how this follows if g is simply smooth.

Any help?
 
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But wait, the norm function is continuous so ||dg/du|| is continuous. Anyone confirm this?
 
It is not that the norm function is continuous as such, but in conjunction with the fact that the derivative of a smooth function is continuous that the result follows..
 
Yes of course. My problem was that I know that dg/du is smooth, hence continuous, but once you apply the norm it may not be necessarily be true that it is continuous anymore. But since the norm is continuous it does follow now as the composition of two continuous functions.

Thanks for your help!
 

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