- #1
apiwowar
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concrete sections for a new building have the dimensions in meters and shapw shown in the figure.
a)find the area of the face of the section superimposed on the rectangular coordinate system.
The way i tried to solve this was to split it up into 2 integrals and add them together to get the area
the integrals were
integral from -5.5 to 0 of 1/3*sqrt(5+x)dx + integral from 0 to 5.5 of 1/3*sqrt(5-x)dx
I tried the first part and got
2/9*(5+x)^(3/2) but when you evaluate it at -5.5 you end up taking the squareroot of a negative number.
Did i do it completely wrong? or did i just make a simple mistake?
any help would be appreciated.
a)find the area of the face of the section superimposed on the rectangular coordinate system.
The way i tried to solve this was to split it up into 2 integrals and add them together to get the area
the integrals were
integral from -5.5 to 0 of 1/3*sqrt(5+x)dx + integral from 0 to 5.5 of 1/3*sqrt(5-x)dx
I tried the first part and got
2/9*(5+x)^(3/2) but when you evaluate it at -5.5 you end up taking the squareroot of a negative number.
Did i do it completely wrong? or did i just make a simple mistake?
any help would be appreciated.
