Calculating Average Balance for 12% Savings Account: Integrals and Banking

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SUMMARY

The discussion focuses on calculating the average balance of a savings account with a $2500 deposit earning 12% interest compounded continuously over two years. The formula used for the principal is P = P₀e^(0.12t), where P₀ is the initial deposit. To find the average balance, participants suggest setting up an integral from 0 to 2 and multiplying the result by 0.5, with the integral representing the continuous growth of the account balance. The correct integral to evaluate is from 0 to 2 of P₀(1 - e^(0.12t)) dt.

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Homework Statement



A deposit of $2500 is made in a savings account earning 12% interest cpmpounded continuously. Find the average balance in the account during the first two years.

Homework Equations





The Attempt at a Solution


I know I'm suppose to set up an integral from 0 to 2 and then multiple the integral by .5. I was just wondering if someone can explain how to set up the actual integral on the inside. I mean I am not sure what equation I'm using.
 
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toasted said:

Homework Statement



A deposit of $2500 is made in a savings account earning 12% interest cpmpounded continuously.
so the principle is given by P= P_0e^1.12t and the interest is P_0(1- e^{1.12t}. That is what you need to integrate from 0 to 2.

Find the average balance in the account during the first two years.

Homework Equations





The Attempt at a Solution


I know I'm suppose to set up an integral from 0 to 2 and then multiple the integral by .5. I was just wondering if someone can explain how to set up the actual integral on the inside. I mean I am not sure what equation I'm using.
 

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