Rapta3
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How do you slove for Mb from this equation (MaVa+MbVb)/Ma+Mb=Vab
The discussion focuses on calculating the average force exerted on a tennis ball during a serve, specifically when the ball leaves the racket at a speed of 62.0 m/s. The mass of the ball is 0.0600 kg, and it is in contact with the racket for 0.0200 seconds. Using the impulse-momentum theorem, the correct average force is approximately 19 kgf, which is insufficient to lift a 60 kg person, as 60 kgf is required for that. The conversation also highlights the importance of unit conversion and correct application of physics principles in momentum calculations.
PREREQUISITESPhysics students, educators, and anyone interested in understanding the mechanics of sports, particularly tennis, and the application of physics principles in real-life scenarios.
Rapta3 said:A tennis ball may leave the racket of a top player on the serve with a speed of 62.0 m/s. If the ball's mass is 0.0600 kg and it is in contact with the racket for 0.0200 s, what is the average force on the ball?
Would this force be large enough to lift a 60 kg person?
large enough or
not large enough
I got .0600x62=3.72
.0200/3.72=.00537
I don't think that is right because that seems way to small but I don't know what I am missing...if it is incorrec that is.
