Calculating Average Recoil Force for Machine Gun Firing 50g Bullets

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SUMMARY

The average recoil force experienced by a machine gun firing 50-gram bullets at a rate of 4 bullets per second, with each bullet leaving the gun at a speed of 1000 m/s, can be calculated using the formula F = Δp / Δt. The correct mass for calculations must be converted from grams to kilograms, resulting in a mass of 0.20 kg. The final calculation yields an average recoil force of 200 N, confirming the importance of unit conversion in physics problems.

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  • Understanding of Newton's laws of motion
  • Knowledge of impulse and momentum concepts
  • Ability to perform unit conversions (grams to kilograms)
  • Familiarity with basic physics equations (F = ma, J = Δp)
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gcombina
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A machine gun fires 50-g bullets at the rate of 4 bullets per second. The bullets leave the gun at a speed of 1000 m/s. What is the average recoil force experienced by the machine gun?

My attempt:
(1) J = FT
F= J/T

so what else should I do?
 
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Well average velocity is total distance divided by total time ... what would average force be?
(Hint: Newtons laws ... how is force related to change in momentum?)
 
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F= J/T= mv/T

Thanks!
 
Well done.
Just checking:- if you traveled in 10s bursts of 10m/s which occur 90s apart - what's the average speed?
The problem you have is actually slightly easier than that.
 
Hello, so I get 200000 g m/s,

what am I doing wrong?
 
Please show your working.
 
J = ft
= (mv) t
= (200g * 1000 m/s) (1s)
= 200 000 gm

* its asking me for the recoil which means the impulse right?
and that is J = ft and what is force? f = mv right? so final formula is J = (mv) (t)
* mass is 200g because of the 4 bullets and velocity is 1000m/s

so I don't know why is wrong, can't see it
 
gcombina said:
J = ft
= (mv) t
Check that equation (J=mvt) by dimemsional analysis.

If "f" is the force in that equation, then you just wrote "force=momentum" ... which is incorrect.
If J is specific impulse, then ##J=\Delta p##

* its asking me for the recoil which means the impulse right?
No - it specifically asks for the average force of the recoil. $$\bar F = \frac{\Delta p}{\Delta t}$$

and that is J = ft and what is force? f = mv right?
No, ##F=ma##.

* mass is 200g because of the 4 bullets and velocity is 1000m/s
Or just use one bullet averaged over 0.25s ... whatever, should get the same number.
But use the right equation, you'll get the right units.
 
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ok

ok I did

F = Δp / Δt

but still I am getting the same bad answer

F = (200 gr/s) (1000 m/s) / (1s)

what is wrong with my equation?
 
  • #10
where did 1 second come from? I did't see that anywhere in the problem.
 
  • #11
gcombina said:
ok I did

F = Δp / Δt

but still I am getting the same bad answer

F = (200 gr/s) (1000 m/s) / (1s)

what is wrong with my equation?

Besides the fact that you're mysteriously dividing by (1s), there seems to be nothing wrong with it.
 
  • #12
cause my equation is F = mv/t

so the time is 1 second (all bullets fired in one second), what else should I put then? any ideas?
 
  • #13
F = (200 gr/s) (1000 m/s) / (1s)
Are you not expected to give Force in SI units?
How do you know you got he wrong answer?
 
  • #14
@Simon, ok i needed to convert 200 gr into kg which is .20 kg and I got 200 N.
Thanks!
 

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