Calculating Battery Internal Resistance: V=IR Method

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SUMMARY

The discussion focuses on calculating the internal resistance of a battery with an electromotive force (emf) of 24V and a terminal voltage of 22V when connected to a 7.5-ohm resistor. The correct internal resistance is determined to be 0.68 ohms. The calculation involves using Ohm's Law (V=IR) to find the current in the circuit and the voltage drop across the internal resistance, which is essential for accurate results.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Familiarity with basic electrical concepts such as emf and terminal voltage
  • Knowledge of series circuits and voltage drops
  • Ability to manipulate algebraic equations for problem-solving
NEXT STEPS
  • Study the calculation of internal resistance in batteries using the formula V = I(R + r)
  • Learn about the impact of internal resistance on battery performance and efficiency
  • Explore methods for measuring internal resistance in practical applications
  • Investigate the differences between ideal and real battery behavior in circuits
USEFUL FOR

Electrical engineers, battery technology researchers, and students studying circuit analysis will benefit from this discussion on calculating battery internal resistance.

accol
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1. A battery is manufactured to have and emf of 24V, but the terminal voltage is only 22V when the battery is connected across a 7.5ohm resistor...what is the internal resistance of the battery?




3. Ok I have the answer already which is .68ohm...but I can't find a way to get to it. At first I tried V=IR or 24=I*7.5 and then plugged that answer into the same equation but with the voltage of 22. I also tried the opposite way. That answer didn't work.

I also tried subtracting the volts from each other to get .27R. Can someone please tell me what I am doing wrong?
 
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Answer these questions:
What's the voltage drop across the internal resistance?
What's the current through the circuit?
Combine these two answers to find the internal resistance.
 

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