- #1
ProPM
- 64
- 0
A body is projected from ground level with a speed of 24 m/s at an angle of 30 degrees above the horizontal. Neglect air resistance and take gravity to be 10 m/s. Calculate:
a) The time taken to reach its highest point
b) The greatest height reached
c) The horizontal range of the body
a) v = u + at
0 = 12 + (-10 x t)
10t = 12
t = 1.2 seconds
b) s = ut + 1/2at^2
s = (12 x 1.2) + (1/2 x -10 x 1.2^2)
s = 7.2 m
c) s = Vertical Velocity (cos 30 x 24) x t
t = 2.4
s = 49.9 m
I tried them, but I am not sure if I made any mistakes.
Can anyone help me?
Thanks!
a) The time taken to reach its highest point
b) The greatest height reached
c) The horizontal range of the body
a) v = u + at
0 = 12 + (-10 x t)
10t = 12
t = 1.2 seconds
b) s = ut + 1/2at^2
s = (12 x 1.2) + (1/2 x -10 x 1.2^2)
s = 7.2 m
c) s = Vertical Velocity (cos 30 x 24) x t
t = 2.4
s = 49.9 m
I tried them, but I am not sure if I made any mistakes.
Can anyone help me?
Thanks!