Calculating Building Height Using Balloon Drop Experiment

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SUMMARY

The discussion focuses on calculating the height of a building using a balloon drop experiment where one balloon is dropped from rest and the other is thrown with an initial speed of 72.52 m/s. Both balloons hit the ground simultaneously after a time difference of 3.7 seconds. The calculations involve using the equations of motion, specifically V=Vi+at and (V^2) - (Vi^2)/(2a)= deltax, leading to a calculated height of approximately 334.73 meters for the building.

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Homework Statement


you and your friend throw balloons filled with water of a roof of a building. You drop yours from rest, he throws his with an initial speed of 72.52 m/s^2 3.7 seconds later. They hit at the same time. How high his the building.


Homework Equations


V=Vi+at
(V^2) - (Vi^2)/(2a)= deltax


The Attempt at a Solution


V=72.52 = 9.81(3.7), V = 108.78
(108.78)^2 - (72.52)^2/(2)(9.81) = deltax
deltax = 334.73 m
 
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seems to me that you have to set up two equations, one for the v0 = 0 at time T and one for v0 = 72.52 m/s at time = (T - 3.7). that's my take...I haven't tried plugging these in, though.
 

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