Calculating Building Height Using the Quadratic Formula

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Homework Help Overview

The problem involves calculating the height of a building from which a watermelon is dropped, considering the time it takes for the sound of the impact to reach the student. The context includes the use of the quadratic formula and the physics of free fall and sound propagation.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive a quadratic equation to solve for the height H by combining terms related to the time of fall and the speed of sound. Some participants suggest combining terms to form a standard quadratic equation, while others question the correctness of the coefficients derived.

Discussion Status

Participants are actively discussing the formulation of the quadratic equation and the correct identification of coefficients. There is an ongoing exploration of the terms involved, with some guidance provided on how to combine them, but no consensus on the final form has been reached.

Contextual Notes

There is a mention of confusion regarding the number of terms in the polynomial and the proper application of the quadratic formula, indicating a potential gap in understanding the setup of the problem.

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Homework Statement



A physics student with too much free time drops a watermelon from the roof of a building height H. He hears the sound of the watermelon going "splat" after a time interval of Delta T.
You may ignore air resistance. How high is the building? The speed of sound is Vs.

Homework Equations



Quadratic formula
physics

The Attempt at a Solution



Ok T = T1 +T2 = H/Vs + sqrt(2H/g)

(T - H/Vs)^2 = 2H/g

Therefore

T^2 - (2TH/Vs) + (H/Vs)^2 - 2H/g = 0

I want to solve for H.
How do I plug this into the quadratic formula so that I can solve for H? I am only used to there being 3 terms in the poly nomial (like x^2 + x + 4). I am thinking I have to combine the -(2TH/Vs) and -2H/g somehow but I don't know how! Please help!
 
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Yes, you combine the two terms, and take out the H. That will leave you with three terms in the form of a quadratic equation.
 
hage567 said:
Yes, you combine the two terms, and take out the H. That will leave you with three terms in the form of a quadratic equation.


Ok I combined them and got H (-2t/Vs - 2/g)

So tell me if this is correct

a = 1/Vs

b = (-2t/Vs - 2/g)

c = t^2

Because when I plug that in as an answer it comes back wrong.
 
One thing I see is that a should be 1/Vs^2.
 

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