Calculating Buoyancy of Steel Boat

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SUMMARY

The discussion focuses on calculating the buoyancy of a steel boat with dimensions 4.00 m x 10.0 m x 4.00 cm, constructed from steel with a density of 7900 kg/m³. The buoyant force (F_buoy) is equated to the weight of the object (W_obj). Participants express confusion regarding the inclusion of the weight of the boat's arms in the calculations and seek clarification on how to determine the boat's waterline depth.

PREREQUISITES
  • Understanding of buoyancy principles
  • Familiarity with the concept of density (specifically, steel density at 7900 kg/m³)
  • Knowledge of basic physics equations, particularly F_buoy = W_obj
  • Ability to perform volume and weight calculations for irregular shapes
NEXT STEPS
  • Research the Archimedes' principle and its application in buoyancy calculations
  • Learn how to calculate the volume and weight of steel structures
  • Explore the effects of additional weight on buoyancy and water displacement
  • Investigate methods for determining the waterline of floating objects
USEFUL FOR

Students in physics or engineering courses, marine architects, and anyone involved in designing or analyzing buoyant structures.

jkb
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1. The bottom of a steel "boat" is a 4.00 m x 10.0 m x 4.00 cm piece of steel (rho=7900). The sides are made of 0.490 cm-thick steel.


Homework Equations



Fbouy = Wobj



The Attempt at a Solution



i have gone around in so many directions that I am pretty much lost...is okay to neglect the weight of the arms and if not then where do I account for this... help!
 
Physics news on Phys.org
What exactly is your question?
 
I assume he wants to find how deep the boat will lie in the water..
(But it might be he is interested in finding out how much water he needs to keep his pot plants alive..)
 

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