GensisLee
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You throw a Frisbee to your friend. The Frisbee has a diameter of 28.0cm and makes one turn in 0.110s. What is the centripetal acceleration at its outer edge?
ac=4π2r/T2
I actually know the answer and how to solve this question...
ac=4π2r/T2
ac=π2(0.14m)/(.100s)2
= 4.57 x 102 m/s2
My question is why is how 0.110s is changed to 0.100s ?
ac=4π2r/T2
I actually know the answer and how to solve this question...
ac=4π2r/T2
ac=π2(0.14m)/(.100s)2
= 4.57 x 102 m/s2
My question is why is how 0.110s is changed to 0.100s ?