Calculating Centripetal Acceleration for a Frisbee in Circular Motion

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SUMMARY

The centripetal acceleration of a Frisbee with a diameter of 28.0 cm, completing one turn in 0.110 seconds, is calculated using the formula ac = 4π²r/T². The radius (r) is 0.14 m, leading to an acceleration of 4.57 x 10² m/s². A point of confusion arose regarding the conversion of the time period from 0.110 seconds to 0.100 seconds, which is confirmed as a typographical error in the discussion.

PREREQUISITES
  • Understanding of centripetal acceleration
  • Familiarity with the formula ac = 4π²r/T²
  • Basic knowledge of circular motion
  • Ability to convert units (cm to m)
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  • Study the derivation of centripetal acceleration formulas
  • Learn about the effects of radius and time on circular motion
  • Explore real-world applications of centripetal acceleration in sports
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Physics students, educators, and anyone interested in understanding the principles of circular motion and centripetal acceleration.

GensisLee
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You throw a Frisbee to your friend. The Frisbee has a diameter of 28.0cm and makes one turn in 0.110s. What is the centripetal acceleration at its outer edge?
ac=4π2r/T2
I actually know the answer and how to solve this question...
ac=4π2r/T2
ac=π2(0.14m)/(.100s)2
= 4.57 x 102 m/s2
My question is why is how 0.110s is changed to 0.100s ?
 
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