Calculating Change in Distance of Two Cars Traveling in Opposite Directions

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SUMMARY

The discussion focuses on calculating the rate of change of distance (z) between two cars, Car A and Car B, traveling in perpendicular directions. Car A moves west at 60 km/hr and Car B moves north at 70 km/hr, intersecting at point O. The problem requires the application of implicit differentiation to the equation z² = x² + y², where x and y represent the positions of the cars relative to point O. The solution involves differentiating the equation with respect to time (t) and substituting the known rates of change for x and y.

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Homework Statement



Car A is traveling west at 60 km/hr.
Car B is traveling north at 70 km/hr.
The cars intersect at point O.
When Car A is x km east of and Car B is y km south of O, the distance between the cars is z km.
Find the rate of change of z when x = .8 km and y = .6 km.

The Attempt at a Solution



In my physics class, we would do this problem with anti-derivatives with initial conditions.
However, in my calc class, we haven't learned this yet.

VA = (-60 km/hr) i

VB = (-70 km/hr) j


So,

rA = (-60t + x) i

rB = (-70t + y) j


z = rB + rB = (-60t + x) i + (-70t + y) j

From here, do I take the derivative of z to get dz/dt?

Also, if someone could tell me how to start this problem without using anti-derivatives, that would be great.
 
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You are given dx/dt, dy/dt and know z2 = x2 + y2, where all the variables are functions of t.

Differentiate this equation implicitly with respect to t and plug your numbers in.
 

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