Calculating Change in Volume at 8.80 km Deep

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SUMMARY

The discussion focuses on calculating the change in volume of 1.00 m3 of water at a depth of 8.80 km in the ocean, where the pressure is approximately 9.08 x 107 N/m2. The density of water at this depth is determined to be 1052.88 kg/m3. Participants debate the use of the formula pv=pv to find the change in volume, emphasizing that the volume does not remain constant under such high pressure conditions.

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starfish794
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Consider a point in the ocean about 8.80 km deep. The pressure at that point is huge, about 9.08 107 N/m2.
(a) Calculate the change in volume of 1.00 m3 of water carried from the surface to this point in the ocean.

I don't get why the answer isn't zero. But anyway, I found the density at that point to be 1052.88 kg/m^3. Should I be using pv=pv to find the change in volume?
 
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starfish794 said:
Consider a point in the ocean about 8.80 km deep. The pressure at that point is huge, about 9.08 107 N/m2.
(a) Calculate the change in volume of 1.00 m3 of water carried from the surface to this point in the ocean.

I don't get why the answer isn't zero. But anyway, I found the density at that point to be 1052.88 kg/m^3. Should I be using pv=pv to find the change in volume?
Someone else is looking at this same problem but with a somewhat different depth number. What information did you use to get that density?

https://www.physicsforums.com/showthread.php?t=143100
 

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