Calculating Charge Flow in Capacitor: 1.02V to 6.78V Battery Swap

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Homework Help Overview

The problem involves calculating the additional charge that flows to the positive plate of a capacitor when the voltage is increased from 1.02 V to 6.78 V. The context is within the subject area of capacitors and charge flow in electrical circuits.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between charge and voltage in capacitors, with one suggesting the use of ratios to find the additional charge. There is also a mention of capacitance being constant during the process.

Discussion Status

Some participants have offered guidance on setting up ratios based on the relationship between charge and voltage. However, there is uncertainty regarding the calculations, as one participant expresses doubt about their result, indicating a lack of consensus on the correct approach.

Contextual Notes

There is a noted absence of capacitance value in the problem, which some participants highlight as a potential barrier to finding a solution.

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Capacitors...Please HELP!

Homework Statement


An uncharged capacitor is connected to the terminals of a 1.02 V battery, and 1.69 μC flows to the positive plate. The 1.02 V battery is then disconnected and replaced with 6.78 V battery, with the positive and negative terminals connected in the same manner as before. How much additional charge flows to the positive plate?


Homework Equations





The Attempt at a Solution


I am not really sure how to start this problem without having the capacitance. Can someone help me get started..thanks!
 
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Can I set these up as ratios?
 
Capacitance is just charge/voltage. You could set up two ratios equal (capacitance isn't changing with additional voltage, but as voltage increases you must increase charge to hold the capacitance constant.
 
So I could do...
1.69x10^-9 C/1.02 V = Q/6.78 V
Q = 1.12x10^-8 C
Then subtract them to get my answer being...
9.54x10^-9 C
 
No that's not right...ahh what am doing wrong??
 

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