Calculating Charge Needed for Same Binding Energy in H2+

Click For Summary
SUMMARY

The discussion centers on calculating the negative charge required to achieve the same binding energy in the H2+ molecular ion, where the protons are positioned 0.106 nm apart with a binding energy of 2.65 eV. The user seeks assistance in determining the appropriate negative charge to place between the two protons to maintain stability, as the protons repel each other. The binding energy is analyzed within the context of a three-charge system comprising two protons and one negative charge, without considering other nuclear forces.

PREREQUISITES
  • Understanding of electrostatic forces and Coulomb's law
  • Familiarity with binding energy concepts in molecular physics
  • Basic knowledge of molecular ion structures, specifically H2+
  • Ability to perform calculations involving energy and charge interactions
NEXT STEPS
  • Study the principles of Coulomb's law and its application in molecular systems
  • Learn about binding energy calculations in multi-charge systems
  • Explore the stability of molecular ions and the role of negative charges
  • Investigate the effects of distance on electrostatic interactions in charged systems
USEFUL FOR

Students and researchers in physics, particularly those focusing on molecular chemistry, electrostatics, and binding energy calculations in charged systems.

ghallya
Messages
16
Reaction score
0
hi I need help in solving this

The protons the H2+ molculer ion are 0.106 nm apart and the binding energy of H2+ is 2.65 ev , what negetive charge must be placed halfway between two protons this distance apart to give the same binding energy?

I calculated it for the electrons , but here i didn know for the protons ?
I tryed to use the graph I had but I don't think its the right solution
so if someone could help me or give an equation I could apply

thanx
 
Last edited by a moderator:
Physics news on Phys.org
Please correct me if I'm wrong...

The two protons repel each other so left to itself, the two proton system is electrostatically unstable. You need a negative charge somewhere between them so that they are both attracted to the -ve charge and effectively stay in place. The binding energy is now defined in terms of the 3 charge system: 2 protons + 1 negative charge. [No other nuclear force is being considered for the mathematical calculations]

Does this help?

PS--Show your work
 

Similar threads

What is the true nature of binding energy in a nucleus?
  • · Replies 1 ·
Replies
1
Views
1K
Conceptual question about binding energy, from OCR paper
  • · Replies 4 ·
Replies
4
Views
2K
Calculating Binding Energy for C13 Neutron Removal
  • · Replies 16 ·
Replies
16
Views
3K
Where is nuclear binding energy stored?
  • · Replies 3 ·
Replies
3
Views
2K
Undergrad Some confusion with the Binding Energy graph of atoms
  • · Replies 13 ·
Replies
13
Views
3K
Why Is Energy Released in Nuclear Decay Equal to Change in Binding Energies?
  • · Replies 13 ·
Replies
13
Views
2K
High School The Effect of Binding Energy on Mass
  • · Replies 5 ·
Replies
5
Views
2K
Archived Binding energy and deuterium nucleus
  • · Replies 1 ·
Replies
1
Views
7K
Calculate Deutron Mass Given Binding Energy
  • · Replies 3 ·
Replies
3
Views
3K
Invariant mass and energy balance
  • · Replies 4 ·
Replies
4
Views
2K