Calculating Charge on a Parallel Plate Capacitor

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SUMMARY

A 5800-nF parallel plate capacitor connected to a 14-V battery has a charge Q calculated using the formula C = Q/V. The correct calculation yields Q = 14 V x 5800 nF, resulting in 81200 nC. However, the answer must be expressed in scientific notation, which is 8.12 x 10^4 nC. The positive plate of the capacitor holds a net charge of +Q, while the negative plate holds -Q.

PREREQUISITES
  • Understanding of capacitor fundamentals
  • Familiarity with the formula C = Q/V
  • Knowledge of scientific notation
  • Basic electrical circuit concepts
NEXT STEPS
  • Learn about the energy stored in capacitors
  • Explore the effects of dielectric materials on capacitance
  • Study the behavior of capacitors in AC circuits
  • Investigate the applications of capacitors in electronic devices
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Students studying electrical engineering, physics enthusiasts, and anyone looking to understand capacitor charging and calculations.

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Homework Statement


A 5800-nF parallel plate capacitor is connected to a 14-V battery and charged.
What is the charge Q on the positive plate of the capacitor?

Homework Equations


C = Q/V

The Attempt at a Solution


This looks like a very simple question. The capacitor is fully charged so 5800 nF = Q/(14 V)
14 V x 5800 nF = 81200 nC

The positive plate will have a +Q net charge and -Q net charge will be on the negative plate.
My answer is incorrect though.
 
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Sorry I am doing this from my iPad. My answer is correct it wanted the answer in scientific notation. Thanks anyways
 

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