Calculating Coefficient of Friction for Olympic Skier

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SUMMARY

The discussion focuses on calculating the coefficient of friction for an Olympic skier descending a 30.0-degree slope at an initial speed of 20.0 m/s, who slides 145 m on wet snow before stopping. The skier's deceleration is determined to be -1.38 m/s². The calculation incorporates both the frictional force and the gravitational acceleration acting along the slope, leading to the conclusion that the coefficient of friction can be derived from the net forces acting on the skier.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with basic kinematic equations
  • Knowledge of forces acting on an inclined plane
  • Concept of friction and its coefficient
NEXT STEPS
  • Calculate the gravitational force component acting down the slope for a 30.0-degree angle
  • Explore the relationship between frictional force and normal force in inclined planes
  • Learn how to derive the coefficient of friction from acceleration and slope angle
  • Investigate real-world applications of friction coefficients in sports physics
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Physics students, sports scientists, and anyone interested in the mechanics of motion on inclined surfaces, particularly in the context of skiing and sports performance analysis.

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Homework Statement


an Olympic skier moving at 20.0 m/s down a 30.0 degree slope encounters a region of wet snow and slides 145 m before coming to a halt. what is the coefficient of friction between the skis and the snow?

Homework Equations


Force of friction = coefficient of friction x Normal Force

The Attempt at a Solution


d = 145 m
vi = 20.0 m/s
vf = 0 m/s
a = -1.38 m/s2
t = 14.5 s
 
Last edited:
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Now you found the acceleration that brought the skier to a stop you must remember that there is also an acceleration due to gravity acting along the slope as well. That means the friction force causes an acceleration that retards the skier and counteracts the acceleration due to gravity.
 

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