- #1

Ering

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## Homework Statement

A 70-kg skier is in a tuck position and moving down a 20-degree hill. Air resistance applies a resultant force of 15 N against the movement of the skier. The coefficient of friction between the skis and the snow is 0.09. What is the resultant downhill force acting on the skier?

## Homework Equations

Force = friction coefficient x normal force

## The Attempt at a Solution

I know you have to break down the force into its x and y components. So making a right triangle with the weight (~700 N: 70kg x 10 m/s2) as the hypotenuse and 70 degrees (90 - the given 20 degrees) as the angle. But after doing that, I'm not sure where to go from there. Is the resultant force also your x-component in the right triangle?