Calculating Coefficients of Friction for a Moving Clock on a Horizontal Floor

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SUMMARY

The discussion focuses on calculating the coefficients of static and kinetic friction (µs and µk) for a 95 kg clock on a horizontal floor. A horizontal force of 650 N is required to set the clock in motion, indicating the static friction coefficient, while a force of 560 N maintains its constant velocity, indicating the kinetic friction coefficient. The formula used is friction force = µ times normal force, where the normal force equals the weight of the clock (mass times gravity).

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Hello, i was abscent two days of last week and this is one of the problems from the homework that I missed. My teacher didn't give me any formula and the notes he gave don't go over this so I am asking for help, thanks a lot Zach.


a 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocit. Find µs and µk between the clock and the floor.
 
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Welcome to PF!

Hi Zach! Welcome to PF! :wink:

Use friction force = µ times normal force. :smile:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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