SUMMARY
The discussion focuses on calculating the Coefficient of Performance (COP) of a refrigerator using the formula COP = Qc/W. The scenario involves cooling 8.43 kg of water from 21.1°C to 4°C using a 0.1655 hp motor over a duration of 9 minutes. The work done by the motor is calculated as W = P(delta)t, resulting in 66670.02 J. The participants emphasize the need to determine the heat removed from the cold reservoir to finalize the COP calculation.
PREREQUISITES
- Understanding of thermodynamics principles, specifically the Coefficient of Performance (COP).
- Familiarity with the concept of work and energy in physics.
- Knowledge of horsepower conversion to watts (1 hp = 746 W).
- Basic skills in unit conversion and calculations involving temperature changes.
NEXT STEPS
- Calculate the heat removed (Qc) from the water during the cooling process.
- Review the principles of thermodynamics related to refrigeration cycles.
- Explore the implications of COP in energy efficiency for refrigeration systems.
- Learn about different types of refrigerants and their impact on COP.
USEFUL FOR
Students in thermodynamics, engineers working with refrigeration systems, and anyone interested in energy efficiency calculations in cooling technologies.