Calculating coulombs with 3 charges

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SUMMARY

The discussion focuses on calculating the total force exerted on a positive charge of 2.6 µC by two negative charges: -2.0 µC located 0.050 m to the north and -4.0 µC located 0.025 m to the south. Participants utilize Coulomb's Law, expressed as F = K(q1*q2)/d^2, where K is 9E9 N m²/C², to determine the forces acting on the positive charge. The challenge lies in correctly calculating the individual forces from each negative charge and combining them while considering their directions.

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  • Coulomb's Law for electrostatic force calculations
  • Understanding of charge interactions (positive and negative)
  • Vector addition for forces in different directions
  • Basic knowledge of microcoulombs (µC) and distance measurements in meters
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  • Study the application of Coulomb's Law in multi-charge systems
  • Learn about vector addition in physics for combining forces
  • Explore the concept of electric fields and their calculations
  • Investigate the influence of distance on electrostatic force
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1. A positive charge of 2.6 µC is pulled on by two negative charges. One, -2.0 µC, is 0.050 m to the north and the other, -4.0 µC, is 0.025 m to the south. What total force is exerted on the positive charge?

north east south west?


2. I'm using the equation Kq1q2/d^2 k=9E9 q=charge r=distance


3. anyone that could help this would be great i tried calculating the force of 1 acting on 3 then 2 acting on 3 and 2 acting on 1 and added them but still no luck anyone that could show how to complete this 3 charge coulomb force would greatly be appreciated
 
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work out the field without the +ve charge, ie the contribution form each -VE charge, be careful with direction then use F = Eq for tehforce on the negative charge

note it only asks for the force on the negative chareg due to the poistive charges
 

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