Calculating critical points and classifying them

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The discussion focuses on finding and classifying critical points for the function f(x,y) = sin(x)sin(y)sin(x+y) within the bounds 0 <= x, y <= Pi. Critical points are identified using the equations x = Pi/3(2n-m) and y = Pi/3(2m-n), where n and m are integers. The second derivative test is proposed for classification, using the determinant fxxfyy - fxy^2 to determine the nature of the critical points. Participants confirm that the second derivative test is appropriate for this analysis. Overall, the method outlined for finding and classifying critical points is deemed correct and effective.
Gekko
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Homework Statement



Find all critical points and classify them


Homework Equations



f(x,y) = sin(x)sin(y)sin(x+y)

0<=x,y<=Pi


The Attempt at a Solution



fx=sinysin(2x+y) and fy=sinxsin(2y+x)

Therefore critical points are at:

x=Pi/3(2n-m) , y=Pi/3(2m-n) where n>=1, m<=2, n,m belong to integer set (Z)

fxx = sin(2x+2y)-sin(2x)
fyy = sin(2x+2y)-sin(2y)
fxy = sin(2x+2y)

Now, to classify the critical points I was simply going to test for:

fxxfyy-fxy^2

If <0 it is a saddle point etc and substitute for x the definitions above to obtain the equation we can use to classify with

Is this correct? Is there a better way? Would greatly appreciate comments. Thanks
 
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Yep, that's the second derivative test. So it's definitely correct (assuming you have that "etc" part right in your comment). As for a better way...there might be something intuitive about this function in particular that makes it special. I don't see anything, but I'm not sure. However, in general, the second derivative test is the way to go.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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