Calculating deacceleration force

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To calculate the force needed to stop an object decelerating from 28 m/s to 0 over a distance of 5 m, the kinematic equation v^2 = 2as can be used, where v is the initial velocity and s is the distance. The mass of the object is 100 kg, and the deceleration can be determined from the equation. Once the deceleration is found, Newton's second law (F = ma) can be applied to calculate the force. The discussion also highlights the challenge of concentrating due to illness, which affects problem-solving ability. Overall, the thread provides guidance on using kinematic equations to solve for force without needing to calculate time.
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Homework Statement



An object is moving at a velocity of 28m/s
The mass is 100kg
It deaccelerates from 28m/s to 0 in a distance of 5m

How much force (N) is needed to stop the object?


Homework Equations




The Attempt at a Solution


I need help, please! :)
 
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You can use one of the kinematic eqations of motion to solve for the deceleration; and then use one of Newton's law to solve for the force. Or use energy methods. Please show what you have tried or your attempt at a solution.
 
Currently I got a 39,4C fever and have problems concentrating.

I understand that I probably need to use the f=ma basic formula but what I can't get my head around is the conversion to time.

Meaning I have the velocity, mass, deacceleration distance, and changes in velocity, still, I can't get my sore head to comprehend how to extract time from it, I´m stuck so unfortunatley I have no formula or attempt to a solution.
 
Valarg said:
Currently I got a 39,4C fever and have problems concentrating.

I understand that I probably need to use the f=ma basic formula but what I can't get my head around is the conversion to time.

Meaning I have the velocity, mass, deacceleration distance, and changes in velocity, still, I can't get my sore head to comprehend how to extract time from it, I´m stuck so unfortunatley I have no formula or attempt to a solution.
Yow, you can't do too much with a 103 (degrees F) temp! Get well soon!

You don't need time; there is a basic kinematic equation that relates velocity with acceleration and distance. For a final velocity of 0, does v^2 = 2(a)(s) sound familiar, where v = 28, and s =5, then solve for a. Take care.
 
You are right, I really should leave this for tomorrow instead!

Thanx a bunch for your help! looks like it solved my problem! :)
 
Valarg said:
You are right, I really should leave this for tomorrow instead!

Thanx a bunch for your help! looks like it solved my problem! :)
I might have given you a bit too much help, but while still working with a 39,4, you deserved it.
 

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