Solving Dynamics Question: F_spring & F_spring Potential

  • Thread starter Thread starter brk51
  • Start date Start date
  • Tags Tags
    Dynamics
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 2K views
brk51
Messages
29
Reaction score
1

Homework Statement


Screen Shot 2017-06-18 at 1.34.48 PM.png


Homework Equations



F_spring = ks and F_spring potential = 1/2ks^2

The Attempt at a Solution



So I recognize that @ theta = 0 it is a 3/4/5 triangle. The length of the spring is at .5m...furthermore the given spring force at that angle is 100 N. So why is it wrong to do 100 = (1/2) (500) (s)^2 ==>> s = .632m... Why should I use F= ks

Everything else I understand...
 
Physics news on Phys.org
Maybe I don't understand what you're trying to do, but it looks like you're plugging in the force of the spring where the potential energy should go.

If you know that the spring applies 500 Newtons for every meter its stretched, if it's applying 100 Newtons, it must have been stretched 0.2 meters (and therefore its normal length is 0.3 meters). That would allow you to find the potential energy in the spring. (Again, if I'm misunderstanding the problem, please tell me).