Calculating Density Using Upthrust and Drag Force in Water

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The discussion revolves around calculating the density of a liquid using the principles of forces acting on a ball reaching terminal velocity. The user initially calculated density using the equation mg = upthrust + drag force, leading to a density value of 884.76 kg/m³, which differed from the answer key's 850 kg/m³. It was identified that the user misinterpreted the drag force equation, where 'v' represents velocity rather than volume. The clarification emphasized the need for proper units in the drag force equation to ensure accurate calculations. This highlights the importance of correctly interpreting variables in physics equations.
jisbon
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Homework Statement
Ball of radius 3cm and mass 0.1kg released from rest in liquid. It eventually reaches terminal velocity at 2m/s. What is density of liquid? Give drag force as F=1.9v
Relevant Equations
Drag force + pgV = mg
So using FBD, I came out with:

1565666320614.png


since it reaches terminal velocity, I can assume F=0, thus mg = upthrust +drag
So my density = mg - drag force/g * volume
However the answer seems to be wrong from the answer key I was given. Any ideas why?
Thanks
 
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jisbon said:
Homework Statement: Ball of radius 3cm and mass 0.1kg released from rest in liquid. It eventually reaches terminal velocity at 2m/s. What is density of liquid? Give drag force as F=1.9v
Homework Equations: Drag force + pgV = mg

So using FBD, I came out with:

View attachment 248071

since it reaches terminal velocity, I can assume F=0, thus mg = upthrust +drag
So my density = mg - drag force/g * volume
However the answer seems to be wrong from the answer key I was given. Any ideas why?
Thanks
Please post your working and answer.
 
haruspex said:
Please post your working and answer.
Volume= 4/3 pi r^3 = 1.13*10^-4
Density = 0.98-(1.9)(1.13*10^-4) / 9.8(1.13*10^-4) = 884.76

The correct answer provided was 850
 
jisbon said:
Volume= 4/3 pi r^3 = 1.13*10^-4
Density = 0.98-(1.9)(1.13*10^-4) / 9.8(1.13*10^-4) = 884.76

The correct answer provided was 850
You appear to have misinterpreted the v in F=1.9v. It refers to the velocity, not the volume.
The 1.9 needs units, e.g. kg/s to take a velocity in m/s and produce a force in N.
 
haruspex said:
You appear to have misinterpreted the v in F=1.9v. It refers to the velocity, not the volume.
The 1.9 needs units, e.g. kg/s to take a velocity in m/s and produce a force in N.
Ah alright, gotem! Thanks for your help :)
 

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