Calculating Density Using Upthrust and Drag Force in Water

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Homework Help Overview

The discussion revolves around calculating the density of a liquid using the concepts of upthrust and drag force, particularly in the context of an object reaching terminal velocity in water. The problem involves a ball of known mass and radius, and the drag force is defined in relation to its velocity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of free body diagrams (FBD) and the assumption of forces being balanced at terminal velocity. There are questions about the interpretation of the drag force equation and its implications for calculating density.

Discussion Status

Participants are actively engaging with the problem, with some providing calculations and others questioning the interpretation of variables in the drag force equation. There is a recognition of potential misinterpretations regarding the relationship between velocity and the drag force coefficient.

Contextual Notes

There is mention of an answer key discrepancy, with participants noting that their calculated density does not match the provided answer. The discussion also highlights the need for clarity regarding units in the drag force equation.

jisbon
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Homework Statement
Ball of radius 3cm and mass 0.1kg released from rest in liquid. It eventually reaches terminal velocity at 2m/s. What is density of liquid? Give drag force as F=1.9v
Relevant Equations
Drag force + pgV = mg
So using FBD, I came out with:

1565666320614.png


since it reaches terminal velocity, I can assume F=0, thus mg = upthrust +drag
So my density = mg - drag force/g * volume
However the answer seems to be wrong from the answer key I was given. Any ideas why?
Thanks
 
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jisbon said:
Homework Statement: Ball of radius 3cm and mass 0.1kg released from rest in liquid. It eventually reaches terminal velocity at 2m/s. What is density of liquid? Give drag force as F=1.9v
Homework Equations: Drag force + pgV = mg

So using FBD, I came out with:

View attachment 248071

since it reaches terminal velocity, I can assume F=0, thus mg = upthrust +drag
So my density = mg - drag force/g * volume
However the answer seems to be wrong from the answer key I was given. Any ideas why?
Thanks
Please post your working and answer.
 
haruspex said:
Please post your working and answer.
Volume= 4/3 pi r^3 = 1.13*10^-4
Density = 0.98-(1.9)(1.13*10^-4) / 9.8(1.13*10^-4) = 884.76

The correct answer provided was 850
 
jisbon said:
Volume= 4/3 pi r^3 = 1.13*10^-4
Density = 0.98-(1.9)(1.13*10^-4) / 9.8(1.13*10^-4) = 884.76

The correct answer provided was 850
You appear to have misinterpreted the v in F=1.9v. It refers to the velocity, not the volume.
The 1.9 needs units, e.g. kg/s to take a velocity in m/s and produce a force in N.
 
haruspex said:
You appear to have misinterpreted the v in F=1.9v. It refers to the velocity, not the volume.
The 1.9 needs units, e.g. kg/s to take a velocity in m/s and produce a force in N.
Ah alright, gotem! Thanks for your help :)
 

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