Calculating DH/dT for a Cone: Understanding dV/dH in the Volume Formula

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Homework Help Overview

The discussion revolves around understanding the derivative of volume with respect to height for a cone, specifically focusing on the expression dV/dH derived from the volume formula V = (πh³)/12. Participants are trying to clarify the relationship between volume and height in the context of related rates.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants express confusion about the transition from the volume formula to the derivative dV/dH, with some seeking clarification on the meaning of this derivative. Others are exploring how to apply differentiation in the context of related rates.

Discussion Status

There is an ongoing exploration of the differentiation process and its implications for the problem at hand. Some participants are attempting to clarify the mathematical steps involved, while others are questioning the application of these concepts in the specific context of the problem.

Contextual Notes

Participants mention a preference for different notations (Leibniz vs. prime notation) and express uncertainty about how to apply the derivative in the context of the problem. The discussion includes references to the chain rule and the relationship between volume and height as functions of time.

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Both the problem and my attempt at a solution are provided. However, I become stuck.

The answer book (question 27, as pictured in the next post, the upload size limit made me create a second post and both images are about 4mb), suggests that I use dV/dH, which is the portion of the cone volume formula: pih^2/4 (once the square is distributed to the radius).

I am having trouble understanding why this part of the formula is considered to be dV/dH, and I am not especially strong in Leibniz notation; I prefer to use prime notation.
I suppose that weakness is catching up with me on this problem.

Thank you in advance for any replies.
 
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The first line of the solution of #27 shows that $$V = \frac{\pi h^3}{12}$$ Are you asking how they get from this to $$\frac{dV}{dh} = \frac{\pi h^2}{4} $$
 
That is exactly what I'm asking, thank you.

Maybe it would help if you explained exactly what dV/dH meant? I think its something like the derivative of V with respect to H...
I get dV/dT meaning flow rate, which makes intuitive sense to me, but I don't understand how the expression shown above equals dV/dH
 
It's straight-forward differentiation. What is the result of $$\frac{d}{dh}(h^3)$$
 
quicksilver123 said:
Maybe it would help if you explained exactly what dV/dH meant? I think its something like the derivative of V with respect to H...
dVdh is the rate of change of volume V with respect to height h.

In this problem, both V and h are functions of time, so differentiate your equation involving V and h with respect to t, using the chain rule.
quicksilver123 said:
I get dV/dT meaning flow rate, which makes intuitive sense to me, but I don't understand how the expression shown above equals dV/dH
 
aie/// i don't get it

well, i get that its the cahnge of volume with respect to height but I'm not sure about how to apply that in this question, as in what expression explains it
 
quicksilver123 said:
aie/// i don't get it

well, i get that its the cahnge of volume with respect to height but I'm not sure about how to apply that in this question, as in what expression explains it
You have ##V = \frac{\pi h^3}{12}##
This is the relationship between V and h. In a related rates problem, you have to get the relationship between the rates (derivatives).

Differentiate both sides of the equation above with respect to t. That will give you dV/dt on the left side. You'll need to use the chain rule to get the derivative with respect to t of the other side.
 

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