Calculating Diameters of Interval Unions

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Homework Help Overview

The discussion revolves around calculating the diameters of unions of intervals, specifically focusing on the definitions and implications of diameter in the context of sets of real numbers.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of diameter for intervals and question how it applies to unions of intervals. There is an attempt to calculate specific diameters for given sets, and some participants raise concerns about the assumptions made regarding subsets.

Discussion Status

There is an ongoing exploration of the definitions involved, with some participants providing calculations and others questioning the correctness of those calculations. The discussion reflects a mix of interpretations regarding the diameter of unions of intervals.

Contextual Notes

Participants note the importance of understanding the definition of "diameter of a set of real numbers" as distinct from just the diameter of an interval. There is also mention of subsets affecting the calculations.

julia89
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I know that the diameter for an interval [a,b] is defined as b-a

but what is
1. Diam of (-1,1]U(2,3)
2.Diam of (1,1/2)U(1/4,1/8)U(1/16,1/32)U...

Thanks
 
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The diameter is defined as the diameter of the smallest interval that contains the set.
 
julia89 said:
I know that the diameter for an interval [a,b] is defined as b-a

but what is
1. Diam of (-1,1]U(2,3)
2.Diam of (1,1/2)U(1/4,1/8)U(1/16,1/32)U...

Thanks
You obviously can't do that unless you know the definition of "diameter of a set or real numbers", not just the diameter of an interval. Fortunately, Dick has provided that.
 
so if i am right

1. Diam of (-1,1]U(2,3)=2+1=3
2.Diam of (1,1/2)U(1/4,1/8)U(1/16,1/32)U...=1/2+1/4+1/16+...

Is this correct?
 
The first one is correct, the second one is not. Did you notice that (1/4, 1/8), (1/16, 1/32), etc. are all SUBSETS of (1, 1/2)? What is (1,1/2)U(1/4,1/8)U(1/16,1/32)U...?
 

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