Calculating Distance and Time with two boats in a river

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Two boats, A and B, are crossing a river that is 72.9m wide, with Boat A aiming for the shortest distance and Boat B for the shortest time. The velocities are 4.90m/s for the boats and 2.50m/s for the river current. The calculations provided initially are incorrect due to not accounting for the vector components of the boats' velocities. Boat A's time to cross should be calculated using the correct width of 72.9m and the appropriate velocity component, while Boat B's time should also consider the river's influence. Understanding how to apply vector components is crucial for accurately determining the crossing times for both boats.
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Homework Statement



Two boats, A and B, travel with a velocity of 4.90m/s across a river with a width of 72.9m. The river flows with a velocity of 2.50m/s. Boat A travels the shortest distance and boat B travels the shortest time. If both start at the same time, how much time will they take to cross the river?

Homework Equations



There are no equations given, but I was able to use this...
Δd/v(boats)+v(river)=shortest time
Δd/v(boats)-v(river)=shortest distance

The Attempt at a Solution


Boat A: (Shortest Distance)
72.0m/(4.9m/s-2.5m/s)=72/2.4=30s

Boat B:(Shortest Time)
72m/(4.9m/s+2.5m/s)=72/7.4=9.7s≈10.0s

My Answer: Boat A can make it in 30s while Boat B can make it in 10s. I did this on a test and missed all of the points possible. Can anyone please help me find my error ansd reach a resonable answer? Thank You!
 
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tajivie said:

Homework Statement



Two boats, A and B, travel with a velocity of 4.90m/s across a river with a width of 72.9m. The river flows with a velocity of 2.50m/s. Boat A travels the shortest distance and boat B travels the shortest time. If both start at the same time, how much time will they take to cross the river?

Homework Equations



There are no equations given, but I was able to use this...
Δd/v(boats)+v(river)=shortest time
Δd/v(boats)-v(river)=shortest distance

The Attempt at a Solution


Boat A: (Shortest Distance)
72.0m/(4.9m/s-2.5m/s)=72/2.4=30s

Boat B:(Shortest Time)
72m/(4.9m/s+2.5m/s)=72/7.4=9.7s≈10.0s

My Answer: Boat A can make it in 30s while Boat B can make it in 10s. I did this on a test and missed all of the points possible. Can anyone please help me find my error ansd reach a resonable answer? Thank You!

Neither boat travels directly with or against the current (so simply adding or subtracting the current speed to the boat's speed is not correct). You have to consider velocity components (vectors). Also, the distance is given as 72.9m and you've used 72m.
 
Sorry, I meant to type 72.0 in the original problem instead of 72.9.
Can you explain to me what you mean by vector components? I know what they are, I am just confused as to how you can apply them to this problem.
 
tajivie said:
Sorry, I meant to type 72.0 in the original problem instead of 72.9.
Can you explain to me what you mean by vector components? I know what they are, I am just confused as to how you can apply them to this problem.
A boat's velocity with respect to the river can have two components; one directed straight across the river, and one directed up or downriver. The component directed straight across moves the boat in the direction of the far shore. Only the one directed up/downriver can influence the boat's motion up/downriver.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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