Calculating Distance in Galilean Transformations

Click For Summary
SUMMARY

The discussion focuses on calculating the distance between two events in a Galilean transformation scenario involving a bus traveling at 24 m/s. The first event occurs when the driver puts on sunglasses, and the second event happens 3.5 seconds later when a passenger drops a pen, positioned 5 meters behind the driver. Using the equation Δx = Δx' + vΔt, the distance separating these events in the Earth's frame of reference is determined to be 84 meters. This calculation incorporates the bus's constant speed and the time elapsed between the two events.

PREREQUISITES
  • Understanding of Galilean transformations
  • Familiarity with relative motion concepts
  • Knowledge of basic kinematics equations
  • Ability to perform calculations involving speed and time
NEXT STEPS
  • Study Galilean transformation equations in detail
  • Learn how to apply relative motion principles in physics problems
  • Explore kinematics problems involving multiple frames of reference
  • Practice solving problems using the equations of motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and motion, as well as educators looking to enhance their understanding of relative motion and Galilean transformations.

aaku516
Messages
10
Reaction score
0

Homework Statement


A bus travels forward at a constant speed of 24 m/s down a straight highway. the driver puts on her sunglasses, and 3.5 s later, a passanger stiing 5 m behind her drops a pen. In the frame of reference of the earth, what is the distance seprating these events?


Homework Equations


x = x' + vt
Δx = Δx' + vΔt
u = u' + v

a = a'


The Attempt at a Solution


Ahh Cannot understand this problem, the part of "relative to the earth" confuses me!
 
Physics news on Phys.org
Suppose that we put a measuring tape inside the bus, with the x = 0 position below the driver seat. Then "relative to the bus", i.e. with respect to this tape, the first even happens at x = 0 and the other event happens at x = 5, right?

Now put a similar measuring tape on the street, exactly such that the driver passes over the x = 0 position as she puts on her sunglasses. At what position with respect to this coordinate system is the passenger that drops the pen 3.5 seconds later?
 

Similar threads

Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
3
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K