Calculating Distance of Block Sliding Down Ramp

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Homework Help Overview

The problem involves a block sliding down a frictionless ramp, with specific heights given for the top and bottom of the ramp. The objective is to calculate the horizontal distance the block travels after leaving the ramp.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss using energy conservation principles to find the velocity of the block and then applying kinematic equations to determine the time of flight and horizontal distance. Some participants express confusion about their calculations and question whether they are applying the correct methods.

Discussion Status

There is an ongoing exploration of different methods to solve the problem, with participants sharing their attempts and results. Some guidance has been offered regarding the equations used, but there is no clear consensus on the correct approach or final answer.

Contextual Notes

Participants note potential confusion regarding the heights involved in the calculations, particularly the difference between the two height values provided. There is also mention of the need to clarify the setup of the problem.

Chrisleo13
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Homework Statement


A 1.79-kg block slides down a frictionless ramp, The top of the ramp is h1 = 1.54 m above the ground; the bottom of the ramp is h2 = 0.287 m above the ground. The block leaves the ramp moving horizontally, and lands a horizontal distance away. Calculate the distance.


Homework Equations





The Attempt at a Solution


I used mg(delta h)=1/2mv^2 to get velocity in the x direction
Then used y=1/2at^2 to find time, I had Viy = 0, g = 9.81 and y = .287

I can't find the distance traveled am I doing something wrong?
 
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Chrisleo13 said:

Homework Statement


A 1.79-kg block slides down a frictionless ramp, The top of the ramp is h1 = 1.54 m above the ground; the bottom of the ramp is h2 = 0.287 m above the ground. The block leaves the ramp moving horizontally, and lands a horizontal distance away. Calculate the distance.

Homework Equations



The Attempt at a Solution


I used mg(delta h)=1/2mv^2 to get velocity in the x direction
Then used y=1/2at^2 to find time, I had Viy = 0, g = 9.81 and y = .287

I can't find the distance traveled am I doing something wrong?

Why not?

It looks like you are all over the method.

You have V2 = 2gh1

You have T2 = 2h2/g

T2*V2 = X2 = 4h2*h1
 
I did it your way as well, but still the wrong result. Ugh, can you work it out and see what you get I got, 1.33 m.
 
Chrisleo13 said:
I did it your way as well, but still the wrong result. Ugh, can you work it out and see what you get I got, 1.33 m.

Actually my h1 was the difference between 1.54 and the .287.

Sorry I didn't see the problem labeled those heights similarly.
 
Thanks, I got it.
 

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