# Calculating Electric Field and Force in a Coaxial Cable

• dimpledur
In summary, the conversation discusses the force on a +25C particle located at D when a 12 V battery is connected to a coaxial cable. The homework equations F=(Vq)/x and Gauss' law are referenced to find the force, taking into account the electric field lines and the non-uniform magnitude between the inner and outer conductor. The radius of the circle is also mentioned.
dimpledur

## Homework Statement

A 12 V battery gets connected between the center conductor (black dot) and the sheath of the coaxial cable so that the voltage of the center conductor with respect to the sheath (outer contour) is +12 V. What is the approximate force on a +25C particle located at D.

## Homework Equations

$$F=(Vq)/x$$

## The Attempt at a Solution

Electric field lines extend from the center conductor to the sheath, with field vectors pointing from the center to the outer contour.

Would the average force then just be $$F=(+12V*+12C)/x$$

and x would merely be measured from the center conductor to the position D?

We're told the radius of the circle is 1cm.

Note that, if you imagine the electric field lines between the inner and outer conductor, that they diverge as they get further from the center. That means that the field won't be a uniform magnitude over all distances as it is with parallel plates.

Have you used Gauss' law before? You should be able to discover the mathematical form of the electric field between the conductors using Gauss' law.

## 1. What is an electric field?

An electric field is a region in space around a charged particle where other charged particles experience a force.

## 2. How is an electric field created?

An electric field is created by a charged particle, such as an electron or a proton, due to its inherent electric charge. It can also be created by an electric potential difference between two points in space.

## 3. What is the direction of an electric field?

The direction of an electric field is defined as the direction that a positive test charge would experience a force if placed in the field. It points away from a positively charged particle and towards a negatively charged particle.

## 4. What is the relationship between electric field and force?

The electric field and force are directly proportional to each other. The force experienced by a charged particle in an electric field is given by the product of the electric field strength and the charge of the particle.

## 5. How is electric field strength measured?

Electric field strength is measured in units of volts per meter (V/m) or newtons per coulomb (N/C). It can be calculated by dividing the force experienced by a charged particle by the charge of the particle.

• Introductory Physics Homework Help
Replies
12
Views
1K
• Introductory Physics Homework Help
Replies
23
Views
2K
• Introductory Physics Homework Help
Replies
1
Views
2K
• Introductory Physics Homework Help
Replies
7
Views
1K
• Introductory Physics Homework Help
Replies
1
Views
2K
• Introductory Physics Homework Help
Replies
7
Views
6K
• Introductory Physics Homework Help
Replies
1
Views
127
• Introductory Physics Homework Help
Replies
2
Views
4K
• Introductory Physics Homework Help
Replies
1
Views
1K
• Introductory Physics Homework Help
Replies
31
Views
1K