Calculating Electric Field and Force in Vector Manipulation Problem

In summary: Ok think I found it you actually have to combine a couple to get it to work. This is one in the book that looks more correct:E=Kq/r^2(r^) - and then this would match the work we did in the recitation class :)In summary, the student is trying to solve an equation for the electric field at a point due to a point charge, but is having difficulty getting started. They eventually find the appropriate equation from a sheet that was given to them, and then use it to find the force in the electric field.
  • #1
Noreturn
49
0

Homework Statement


1. Calculate the electric field at field point 3i + 6j created by a 5.50uC electric charge at 13i + 8j

2. Calculate the electric force on an electron at field point 3i + 6j and in the same electric field calculated
for the prior problem.

Homework Equations


The Attempt at a Solution


Going to combine 2&3 together to see how far I get

So I know I need to find the difference of the two so:

3-13= 10i
6-8= -2j

|r|=sqrt (10^2-2^2) =sqrt (104)

Then I have r^=10/sqrt(104)i+2/sqrt(104)j

Then that is where I get lost there like some many equations to choose from I do not know which one to use.

Cause electric field= force/charge.

So would it be r^/5.5uC?
 
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  • #2
Noreturn said:
Then I have r^=10/sqrt(104)i+2/sqrt(104)j
You need a negative sign in front of the y-component. Also, it would help writing down all those equations that you have and are relevant. Then we could help you choose.
 
  • #3
kuruman said:
You need a negative sign in front of the y-component. Also, it would help writing down all those equations that you have and are relevant. Then we could help you choose.

Well it's just a test equation sheet it's a full page of equations. Here is some of the equations he gives us. Kinda hard to follow but they are there.
https://imgur.com/bnpPbng
 
  • #4
If you are about to take a test and this sheet was given to you to study from, it will be an excellent idea for you to know (a) what the symbols in these equations stand for and (b) when these equations are applicable. Here you want equations that are applicable to the electric field due to a point charge. Which one(s) do you think fit the bill?
 
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  • #5
Would it be E=Kq*r^?

So
E=(9*10^9)(5.5x10^-6/sqrt(104))(-10i-2j/sqrt(104)

E= -467i-93.3j
 
  • #6
Noreturn said:
Would it be E=Kq*r^?
No it would not. This equation is not even on the sheet you posted.
 
  • #7
Which one is it suppose to be? I was following notes that we took in recitation and that was the final answer he came up with.
 
  • #8
The formula sheet that you were given shows equations that are starting points for solving problems. They are not final answers. If
Noreturn said:
... that was the final answer he came up with.
then that is an answer in the context of the problem that he solved, not necessarily something you can use for the problem you posted. You need to go back to the sheet and find the appropriate equation as I indicated in post #4. You have to learn how to do this on your own, else the equations sheet will be useless to you during a test.
 
  • #9
So the only equation if I am looking right is:

E=Fon q/Q

So would it be (-10i-2j/sqrt(104))/(5.5*10^-6)
 
  • #10
That's the equation you should use to find the force in part 2. You still need to find the electric field at that point (part 1). Take a good look at all the equations on your sheet. You are probably on the brink of being frustrated, but you have to learn to be methodical.
 
  • #11
kuruman said:
That's the equation you should use to find the force in part 2. You still need to find the electric field at that point (part 1). Take a good look at all the equations on your sheet. You are probably on the brink of being frustrated, but you have to learn to be methodical.

Ok think I found it you actually have to combine a couple to get it to work. This is one in the book that looks more correct:

E=Kq/r^2(r^) - and then this would match the work we did in the recitation class :)
 
  • #12
That's the one. You already have ##\hat{r}## so go for it.
 

1. What is a vector manipulation equation?

A vector manipulation equation is a mathematical expression that involves operations on vectors, which are quantities that have both magnitude and direction. These equations are used to perform calculations involving vectors, such as addition, subtraction, multiplication, and division.

2. How is a vector manipulation equation different from a regular equation?

The main difference between a vector manipulation equation and a regular equation is that a vector manipulation equation involves vectors, which are multidimensional quantities, while a regular equation involves only scalars, which are one-dimensional quantities. Vector manipulation equations also take into account the direction of the vectors, while regular equations do not.

3. What are some common examples of vector manipulation equations?

Some common examples of vector manipulation equations include the dot product, cross product, and scalar projection. These equations are used in various fields of science and engineering, such as physics, mechanics, and electromagnetism.

4. How are vector manipulation equations used in real-world applications?

Vector manipulation equations are used in real-world applications to model and solve problems involving multidimensional quantities. They are used in fields such as computer graphics, robotics, and navigation systems. For example, in computer graphics, vector manipulation equations are used to rotate and scale objects in 3D space.

5. Are there any special rules or properties for vector manipulation equations?

Yes, there are several rules and properties that apply to vector manipulation equations. These include the commutative, associative, and distributive properties, as well as the fact that the order of operations matters. It is also important to note that vector manipulation equations must be performed on vectors of the same dimensions.

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