Calculating Electric Field from Force on a Point Charge

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To calculate the electric field at a point where a 1.20 µC charge experiences a force of (3.0 î - 5.0 ĵ) × 10^-3 N, the relevant relationship is F = QE, where F is the force, Q is the charge, and E is the electric field. The initial equation provided, E = KQ/d^2, is not applicable in this context. Instead, using the formula F = QE allows for direct calculation of the electric field from the given force. Visualizing the problem can be challenging, but focusing on the force and charge relationship clarifies the concept. Understanding this relationship is key to solving the problem effectively.
Benjamin
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Homework Statement


What is the electric field at a point when the force on a 1.20 µC charge placed at that point is
boldF.gif
= (3.0 î -5.0 ĵ) × 10-3 N?

Homework Equations


E = KQ/d^2

The Attempt at a Solution


I'm having trouble visualizing the question. I attempted to draw it out, but its not making sense. Not asking for the answer, just an explanation of the problem. Thank you
 

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Hi Benjamin and welcome to PF.

The equation you posted is not very relevant. What is another equation that directly relates force and electric field?
 
kuruman said:
Hi Benjamin and welcome to PF.

The equation you posted is not very relevant. What is another equation that directly relates force and electric field?
Benjamin said:

Homework Statement


What is the electric field at a point when the force on a 1.20 µC charge placed at that point is View attachment 219285 = (3.0 î -5.0 ĵ) × 10-3 N?

Homework Equations


E = KQ/d^2

The Attempt at a Solution


I'm having trouble visualizing the question. I attempted to draw it out, but its not making sense. Not asking for the answer, just an explanation of the problem. Thank you
The answer gives the explanation in this case.Force and electric field are related by the formulae :F=QE .Using this you can calculate the electric field .
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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