Calculating Electric Field Strength Between Two Disks with 24 Volt Power Supply

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Homework Help Overview

The discussion revolves around calculating the electric field strength between two disks connected to a 24-volt power supply. The original poster is attempting to determine the electric field at a midpoint between the disks, which are separated by 24 cm and placed on carbon impregnated paper.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the setup of the disks and the implications of the voltage applied. Questions arise regarding the charge on the disks and the interpretation of the distance between them. There is also a focus on measuring potential differences and plotting equipotential lines.

Discussion Status

Some participants have provided insights into measuring potential and calculating electric field strength using the relationship between voltage and distance. The conversation reflects a mix of interpretations and clarifications regarding the setup and measurements involved.

Contextual Notes

There is uncertainty about the charge on the disks and how to accurately determine it. The original poster mentions using a voltmeter to find equipotential lines, but questions remain about the exact nature of the setup and the definition of the midpoint between the disks.

yoleven
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Homework Statement


If I have a 24 volt power supply.The positive lead is attached to a disk and the negative lead is attached to another. The disks are separated by about 24 cm. The disks are on a sheet of carbon impregnated paper. Is the charge on the disk 24 volts?

I am trying to determine the electric field strength at a point directly in the middle of the two disks.

E= 2*8.99x10^9*q/r^2

but I am not sure what the charge is on the sphere.
 
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You've got me confused, or at least the question has! Am I correct in picturing the two disks sitting flat on carbon paper with 24 cm between their outer edges?
Under these circumstances, I don't think it is possible to determine the charges on the disks, if any. Where is the sphere?

How could their be a single point in the middle of both disks?
 
Thanks for responding.
Sorry for the confusion.
I am supposed to chart the electric field between two point charges.
And determine the excess charge on each sphere.

The carbon impregnated paper is used to model the electric field in a plane that passes through the center of two spheres. In this case, pennies.

So basically, I attached the positive lead from the power source 24v to one disc and the negative lead to the other.

I attached the negative lead of a voltmeter to the negative disc and used the positive to find the 4v,8v,12v,16v, and 20v equipotential lines on the paper. These locations I plotted on to a graph paper.

I need to calculate the electric field strenght at a point b which is the intersection of a straight line that runs through the center of the discs and the 12 v equipotential line.

I know the distance between the discs but I am not sure what the charges on the discs would be.
 
Oh, interesting! You can actually measure the potential anywhere and find the lines. E field lines are perpendicula to equipotential lines. Neat.

With all that information, you could use E = V/d to find the potential. Here "V" should be a delta V, the difference in potential between two points at the location you are interested in. Measure the potential difference and the distance between the two points - then you can calculate the Electric field strength.
 
Thank you, I appreciate your response. It helped.
 

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