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K3nt70
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Homework Statement
A 1.3microC point charge is placed at the center of a cube with a volume of 9.8m^3. Calculate the electric flux through one side of the cube.
Homework Equations
E = [tex]\frac{k*q}{r^2}[/tex]
[tex]\Phi[/tex] = E*A
The Attempt at a Solution
So what i was trying was this:
I cube root the volume of the cube. This gives me the length of any side since its a cube. So then, i calculate E where k = 9.0E9 q = 1.3E-6 and r = 1.07 (this is half of one length of one side). I then put E back into the electric flux equation where A is (2.14^2)*6 (the total surface area of the cube) i then take my answer and divide by 6 to get the flux for one side which comes out to 4.68E4 N*m^2/C which is incorrect. I am thinking I've made a mistake calculating the Electric field (the r value specifically, since it isn't really constant. ie if we wanted to know the flux in the corner of the cube, we would need to use trig to get the r value. But i can't see what else the r value would be.) A little direction would be great :D
my picture (not given):
http://img214.imageshack.us/img214/1397/chargeyp3.png
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