Calculating Electron Deflection in CRT

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SUMMARY

The discussion focuses on calculating the deflection of electrons in a cathode-ray tube (CRT) under the influence of an electric field. The key equation derived is d = 1/2 * eV/mw * l^2/v0^2 + eV/mw * L/v0, where e is the charge of an electron, V is the applied voltage, w is the distance between the plates, l is the distance traveled between the plates, and v0 is the initial velocity. The participants clarify that the slight deflection between the plates is neglected, which explains the discrepancy in the expected solution. Newton's second law and kinematic equations are utilized to arrive at the final expression for deflection.

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Homework Statement



In the cathode-ray tube, electrons having a mass m
are emitted from a source point S and begin to travel
horizontally with an initial velocity v0. While passing
between the grid plates a distance l, they are subjected to a
vertical force having a magnitude eV/w, where e is the
charge of an electron, V the applied voltage acting across
the plates, and w the distance between the plates. After
passing clear of the plates, the electrons then travel in
straight lines and strike the screen at A. Determine the
deflection d of the electrons in terms of the dimensions of
the voltage plate and tube. Neglect gravity which causes a
slight vertical deflection when the electron travels from S to
the screen, and the slight deflection between the plates.

See attachment for picture

Homework Equations



∑Fy = may

vy = ayt

The Attempt at a Solution



By Newton's 2nd Law,

ay = eV/mw from 0 to l

By kinematics t1 = l/v0
t2 = t1 + L/v0 = l/v0 + L/v0

From 0 to l, by kinematics:

y1 = 1/2*eV/mw*(l/v0^2)
(v1)y = eV/mw*l/v0

Hence, from l to L where ay is zero

y2 = d = 1/2*eV/mw*l^2/v0^2 + eV/mw*L/v0

It appears the solution is missing the left term I keep getting, any idea why?
 

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The solution is missing that term because they are neglecting the slight deflection between the plates, as mentioned at the end of the problem statement.
 
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