Calculating electrostatic pressure

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SUMMARY

The discussion focuses on calculating the number of electrons required to create an electrostatic pressure of one atmosphere on a spherical balloon made of aluminum-coated Mylar with a radius of 1.0 m. The solution involves applying Gauss's Law, where the electric field, E, is defined as ##\vec E=\frac {q}{4\pi R^2 \epsilon}\hat r##. The relationship between electric pressure and surface charge is emphasized, noting that the repulsion among charges causes the balloon's surface to expand. The concept of virtual work is suggested as a method to quantitatively analyze the problem.

PREREQUISITES
  • Understanding of Gauss's Law in electrostatics
  • Familiarity with electric field concepts and equations
  • Knowledge of electrostatic pressure and its implications
  • Basic principles of virtual work in physics
NEXT STEPS
  • Study the application of Gauss's Law in different geometries
  • Explore the relationship between electric field and surface charge density
  • Investigate the concept of electrostatic pressure in conductors
  • Learn about virtual work and its applications in electrostatics
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Students and educators in physics, particularly those focusing on electrostatics, as well as engineers working with materials that involve electrostatic properties.

June_cosmo
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Homework Statement


Calculating electrostatic pressure. A spherical balloon with radius 1.0 m is made of aluminum-coated Mylar. How many electrons must be deposited on the aluminum layer such that the resulting electric pressure is equal to one atmosphere?

Homework Equations

The Attempt at a Solution


Assume q is the total charge of electrons needed, on the sphere using Gauss's Law, ##\vec E=\frac {q}{4\pi R^2 \epsilon}\hat r##. For one infinitesimal on sphere, ##\vec F=\vec E*d_q, where F=F_{atmosphere}##
I checked out other questions and found this method may not be right..
 
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Maybe it is similar to the process of pressurizing a balloon by adding more and more gas to it it, that is the "electric pressure" increases as more and more electrons are brought onto the surface of the balloon? According to Wiki an electrostatic pressure is exerted on a section of a surface charge on a conductor due to the electric field, E, at that point. Strangely enough it says that this pressure tends to push the surface charge into the conductor's surface? As far as I know the electric field is perpendicular to the surface of the conductor. Which makes this statement difficult to understand. I see that this problem is also discussed in the "Electrostatic pressure" Similar discussion link below.
 
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The charges all repel each other so it is clear that there is a force acting to push the balloon's surface outward. For example, think of a thin strip about the "equator" - all the charges repel each other so they're trying to get away from each other radially outwards. (That's why, on a charged solid sphere, they're all on the ouside surface!)

OK, as to the quantitaive aspect - I suggest considering virtual work! From an energy viewpoint this is not a difficult problem.
 
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