Calculating EMF in Steel Beam Impact Before Landing

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SUMMARY

The discussion focuses on calculating the electromotive force (emf) generated in a steel beam, measuring 11.2 meters in length, dropped from a height of 9.51 meters, while exposed to a horizontal magnetic field of 18.5 x 10^-6 T. The relevant equation for emf is given as e = magnetic flux / time. The area of the beam's impact is calculated using the formula for the area of a triangle, A = 1/2 * base * height, resulting in an area of 53.36 m². However, the absence of a time variable in the calculations raises questions about the completeness of the solution.

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with the formula for calculating area (A = 1/2 * base * height)
  • Knowledge of magnetic flux and its relation to emf
  • Basic physics concepts related to forces on charged particles
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  • Research the concept of magnetic flux and its calculation in electromagnetic systems
  • Study the relationship between emf and time in electromagnetic induction scenarios
  • Explore the effects of gravitational potential energy on falling objects
  • Learn about the forces acting on charged particles in magnetic fields
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Physics students, electrical engineers, and anyone interested in the principles of electromagnetic induction and its applications in real-world scenarios.

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Homework Statement



A 11.2m long steel been is dropped from a height of 9.51m. The horizontal component of the Earth's over the region is 18.5x10^-6T. What's the emf in the beam impact just before the impact with the earth, assuming its long dimension remains in a horizontal plane, oriented perpendicularly to the horizontal component of the Earth's magnetic field?

Homework Equations


e= mag flx/t


The Attempt at a Solution


A= 1/2*b*h
A=1/2 x 11.2 x9.51= 53.36

18.5e-6* 53.26
but there's no time
 
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xswtxoj said:

Homework Statement



A 11.2m long steel been is dropped from a height of 9.51m. The horizontal component of the Earth's over the region is 18.5x10^-6T. What's the emf in the beam impact just before the impact with the earth, assuming its long dimension remains in a horizontal plane, oriented perpendicularly to the horizontal component of the Earth's magnetic field?

Homework Equations


e= mag flx/t


The Attempt at a Solution


A= 1/2*b*h
A=1/2 x 11.2 x9.51= 53.36
That would be the area of a triangle, but I fail to see the relevance?

18.5e-6* 53.26
but there's no time

My own hunch is that the electric and magnetic forces on a test charge Q in the beam would have to be equal in magnitude, opposite in direction.

So, what is the magnetic force on a charge Q?
 

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