How Close to the End Can Suki Walk Before the Beam Tips?

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Homework Help Overview

The problem involves a steel beam that is 6.50 m long and weighs 354 N, supported at two points 3.00 m apart. A person named Suki, weighing 535 N, stands on the beam and walks towards one end. The question is to determine how close she can walk to the end before the beam tips.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of a pivot point for analyzing the forces acting on the beam. There are attempts to visualize the problem through drawings and to split the beam's weight for calculations. Questions arise about the correct method to determine the center of mass and the weight distribution on either side of the pivot.

Discussion Status

Participants are actively engaging with the problem, offering suggestions on how to approach the calculations. Some guidance has been provided regarding the need to identify the pivot point and to consider the center of mass for both the beam and Suki. There is no explicit consensus yet, as different interpretations of the problem are being explored.

Contextual Notes

There is uncertainty regarding the correct setup for the pivot point and how to accurately divide the beam's weight. Participants are also grappling with the implications of Suki's position relative to the tipping point of the beam.

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Homework Statement


A steel beam that is 6.50 m long weighs 354 N. It rests on two supports, 3.00 m apart, with equal amounts of the beam extending from each end. Suki, who weighs 535 N, stands on the beam in the center and then walks toward one end. How close to the end can she come before the beam begins to tip?



Homework Equations



unsure what to use

The Attempt at a Solution



This problem is confusing for me, I tried drawing a picture and am unsure if it is correct, so I have no idea how to solve this or attempt this in a correct way
 
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Draw a picture.

Now choose either support as a pivot point.

On one side you have the center of mass of that part of the beam acting over its distance to the pivot. On the other side you have Suki and the center of mass of the other side of the beam. The moment little Suki slides past the distance to maintain balance is where it all comes apart doesn't it?
 
So I "split" the beam in half so the left side would be
177N and the other half with Suki would be 712N

How would i go from there?
 
halo9909 said:
So I "split" the beam in half so the left side would be
177N and the other half with Suki would be 712N

How would i go from there?

No.

You need to split the weight of the beam between each side of the pivot point. The center is not the pivot point. You need to calculate where the support point that it will pivot about is on the beam first. Then divide the weight between the 2 sides.

But even after you find the weight division you still need to find the center of mass for each of those sides of the beam.

Suki*distance + part beam center of mass*distance = other part beam center of mass*distance.
 

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