Calculating Energy Dissipated in Copper Wire Loop Due to Magnetic Field Increase

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SUMMARY

The discussion focuses on calculating the average electrical energy dissipated in a copper wire loop due to an increasing magnetic field. A circular loop with a radius of 9 cm experiences a magnetic field increase from 0 to 0.45 T over 0.45 seconds, resulting in an electromotive force (emf) of 0.254 Volts. The wire has a resistance per unit length of 3.3 x 10-2 ohms/m. To find the energy dissipated, one must first calculate the current flowing through the wire.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Knowledge of Ohm's Law
  • Familiarity with calculating resistance in circular loops
  • Basic principles of electrical energy dissipation
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  • Calculate the total resistance of the copper wire loop
  • Determine the current using Ohm's Law with the calculated resistance and emf
  • Research the formula for electrical energy dissipation in resistive circuits
  • Explore the implications of magnetic field changes on induced currents
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A piece of copper wire is formed into a single circular loop of radius 9 cm. A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to 0.45 T in a time of 0.45 s. The wire has a resistance per unit length of 3.3 10-2 /m. What is the average electrical energy dissipated in the resistance of the wire.


I know the emf = 0.254 Volts.

How do I find the energy dissipated?
 
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Start by finding the current that flows through the wire.
 

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