Calculating Energy Released from Uranium Fission

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SUMMARY

The discussion focuses on calculating the energy released from a mass of uranium during nuclear fission using Einstein's formula, E=mc². A mass of 3.33x10^-28 kg of uranium is converted into energy, resulting in an energy release of 2.997x10^-11 J. The calculations demonstrate the application of the speed of light, c = 3x10^8 m/s, in determining the energy output. The final result confirms the energy released during the fission process.

PREREQUISITES
  • Understanding of Einstein's mass-energy equivalence formula (E=mc²)
  • Basic knowledge of nuclear fission processes
  • Familiarity with scientific notation and unit conversions
  • Concept of the speed of light in a vacuum (c = 3x10^8 m/s)
NEXT STEPS
  • Study the principles of nuclear fission and its applications in energy production
  • Learn about the implications of mass-energy equivalence in physics
  • Explore advanced calculations involving energy release in different nuclear reactions
  • Investigate safety measures and environmental impacts of nuclear energy
USEFUL FOR

Students in physics, nuclear engineers, and anyone interested in the principles of energy conversion in nuclear reactions.

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Homework Statement




a mass of 3.33x10^-28kg of uranium is converted into energy during nuclear fission (exploding) according to einstein's formula

E=mc^2
where energy is measured in joules (J), m is measured in kg and c = 3000000000m/s is the speed of light

Homework Equations



show that the amount of energy released during fission is 2.997x10^-1 J

The Attempt at a Solution




E = mc^2
= 28kg x (3x10^8ms^-1)^2
= 28kg x (3x10^8ms^-1)x(3x10^8ms^-1)
= 28kg (9x10^16m^2s^-2)
= 28 x (9x10^16)kg m^2s^-2
= 252 x 10^16 J
= 2,520,000,000,000,000

thats my attempt.. i know nothing about this stuff and i was trying to do this for a friend.. I am curious now what others come up with
 
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[itex]m = 3.33\times 10^{-28}[/itex]

[itex]c = 3\times 10^8[/itex]

[itex]E = mc^2[/itex]

[itex]E = (3.33\times 10^{-28})(3\times 10^8)^2 = 2.997\times 10^{-11}[/itex]
 

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