pivoxa15 said:
What would you do if you were asked to calculate the entropy of an object such as an apple? Does the question even make sense?
Well, you'd have to count all the different microscopic arrangements of the particles in the apple which would still be compatible with your description of "apple". This number, N, is then entered in Boltzmann's formula:
S = k ln N
with k = Boltzmann's constant, and it will give you the entropy.
k = 1.38 10^(-23) Joule/Kelvin
As you see, the concept of entropy is in principle dependent of the precision by which you describe your apple, but this is usually taken as "macroscopically distinct" descriptions. And, when you look at it numerically, it really doesn't change much the value of S when you add, or leave out, an extra macroscopic specification.
This is because even if your macroscopic description changes the number N of compatible states, by, say, a factor 10^50, this would only change your entropy by k x ln 10^50 ~ k x 150 ~ 10^(-20) Joule/Kelvin, an utterly small amount of entropy.