Calculating {erf}(x) Without Computers?

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Homework Help Overview

The discussion revolves around calculating the error function, erf(x), without the use of computational tools. Participants explore whether it is possible to evaluate this function through analytical means or numerical methods.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the possibility of finding an elementary anti-derivative for erf(x) and consider numerical integration methods, including Taylor series and Simpson's rule, as potential approaches for evaluation.

Discussion Status

The conversation is ongoing, with participants sharing insights about the limitations of direct evaluation and the necessity of numerical methods. There is no explicit consensus, but various methods are being explored and discussed.

Contextual Notes

Some participants mention the existence of a closed form expression for erf(x) for large values of x, indicating that different contexts or constraints may influence the discussion.

LM741
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Hi guys...
don't suppose anybody knows how to calculate the error function - erf(x)

I know Matlab can calculate it - but is it possible to evaluate it without computational techniques (i.e. using computers)?

[tex]{erf}(x) = \frac{2}{\sqrt{\pi}}\int_0^x e^{-t^2} dt.[/tex]

Would appreciate any feedback.

thanks.

The link below will direct you to a website where the equation can be viewed...

http://images.planetmath.org:8080/cache/objects/6429/l2h/img2.png
 
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If you mean "Is there an elementary anti-derivative" that can be evaluated directly, the answer is no. The only way to evaluate erf(x) is to do a numerical integration.
 
thanks...
by numerical integration do you mean applying Tayler Series and expansions like that?
 
I was thinking more of Simpson's rule.
 
LM741 said:
thanks...
by numerical integration do you mean applying Tayler Series and expansions like that?

actually, with a computer program to calculate the terms and summation, that is what they do. one thing is that there is a nice closed form expression for the erf(x) for large x.

see http://mathworld.wolfram.com/Erf.html for some detail.
 
thanks guys!
 

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