Calculating Field Direction and Magnitude for Levitating Copper Wire

g.gnunu
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how do i find the field direction and magnitude of a horizontal copper wire with a current moving East. length is 1.0m, diameter is .10cm, current is 50 A. the wire is being levitated.
 
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Use F=ILXB=mg.
 
field direction and magntiude

could you polease expand on the formula. what numbers do i plug in for mg?
 
m - mass of the wire
g - 9.81N/Kg. The force which a 1Kg mass exerts due to gravity.
 
g.gnunu said:
could you polease expand on the formula. what numbers do i plug in for mg?
The important thing isn't knowing which numbers to plug in where, it's understanding the principles behind the equation and where the equation comes from. Do you understand where the equation comes from?
 
Last edited:
how do i set up the formula to get the answer?
 

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